The-matlab--Classic-Tutorials

INS demo processing file

特征提取算法（pca),用于数据的特征提取。(feature extraction)

当文件的某一行存在某一个字符串时，就删除该文件的那一行，并适应于多文件的批量处理。(When a file on a row exists a string, delete the line of the file, batch processing and is suitable for multiple file.)

这是一个很实现的MATLAB实现JPEG源程序,希望对大家有帮忙(This is a very achievable JPEG source MATLAB to achieve, in the hope that we have to help)

小数分频PLL的matlab源代码，包含二阶sigma-delta调制器的源码。(Fractional PLL the matlab source code)

Bi-dimensional Gabor filter with DC component compensation This version of the 2D Gabor filter is basically a bi-dimensional Gaussian function centered at origin (0,0) with variance S modulated by a complex sinusoid with polar frequency (F,W) and phase P described by the following equation: G(x,y,S,F,W,P)=k*Gaussian(x,y,S)*(Sinusoid(x,y,F,W,P)-DC(F,S,P)), where: Gaussian(x,y,S)=exp(-pi*S^2*(x^2+y^2)) Sinusoid(x,y,F,W,P)=exp(j*(2*pi*F*(x*cos(W)+y*sin(W))+P))) DC(F,S,P)=exp(-pi*(F/S)^2+j*P) File Id: 13776 Average rating: 0.0 Size: 1 KB # of reviews: 0 Submitted: 2007-01-26 Downloads: 274 Subscribers: 0 Keywords: gabor filter Stiven Schwanz Dias (Bi-dimensional Gabor filter with DC compo .. compensation This version of the 2D Gabor f ilter is basically a bi-dimensional Gaussian f unction centered at origin (0, 0) with variance S modulated by a complex sinuso id with polar frequency (F, W) and phase P described by the following equati on : G (x, y, S, F, W, P) = k* Gaussian (x, y, S)* (Sinusoid (x, y, F, W, P)- DC (F, S, P)), where : Gaussian (x, y, S) = exp (-pi* S* 2 ^ (x ^ 2 y ^ 2)) Sinusoid (x, y, F, W, P) = exp (j* (2* pi* F* (x* cos (W) y* sin (W)) P))) D C (F, S, P) = exp (-pi* (F/S) ^ 2* P j) File Id : 13776 Average rating : 0.0 Size :# 1 KB of reviews : 0 Submitted : 2007-01-26 Downloads : 274 Subscribers : 0 Keywords : gabor filter Stiven Schwanz Dias)

huffman dec2..........................................

matlab仿真无线信道各种衰落特性（瑞利衰落），调制方式为QPSK(the matlab simulation wireless channel fading characteristics (Rayleigh fading), QPSK modulation)

说明：  计算在一个矩形里，用同等大小圆来覆盖这个区域，所需要的最小圆个数，我已经运行过(Calculated in a rectangle, the circle with the same size to cover the region, the minimum required for a round number, I have to run-off)

matlab与vc混合编排的问题，可以得到有效解决，详细介绍后还有编码实现哦(Matlab and vc mixed scheduling issues can be effectively resolved After detailed There Coding oh)