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Year
一个判断年份,是闰年还是平年的小工具,可以非常方便的查询个个年份(A judge year, or a non-leap year is a leap year a small tool that can be very convenient to check everybody Year)
- 2010-02-08 17:15:15下载
- 积分:1
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qxnh00005
用c++编的matlab曲线拟合程序,都是老师布置的数值分析作业!希望和大家交流.谢谢网站提供这个平台!(c addendum to the use of curve fitting procedures Matlab, Layout of the teachers are numerical analysis operations. We hope and exchanges. Thank you for providing this platform!)
- 2006-10-15 20:02:35下载
- 积分:1
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matlab_rtw_c
(1)通过Simulink创建仿真模型;(2)配置相关RTW(Real-Time Workshop)参数;(3)通过RTW(Real-Time Workshop)自动生成C代码文件,并理解主要文件、接口函数和变量的意义;(4)在Visual C++中将生成的C代码作适当修改,编译运行并分析结果。((1) created by Simulink simulation model (2) configuration related to RTW (Real-Time Workshop) parameters (3) RTW (Real-Time Workshop) automatically generate C code files, and understand the main document, interface functions and variables significance (4) Visual C++ generated C code will be modified as appropriate, compile, run and analyze the results.)
- 2011-01-09 23:00:25下载
- 积分:1
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art-cpp
《實戰C++ — 八個別具特色的實作經驗》與目前市面㆖ 眾多C++ 書籍的最大不同,在於
本書既非基礎觀念之教㈻ 書籍,亦非開發工具之使用手冊,而是以「㆒ 章㆒ 專案」的方式,
從實際應用面引領讀者領略C++。
本書是《The Art of C++》的㆗ 文譯本。原作者Herbert Schildt 是㆒ 位㈻ ㈲ 專精、著作等身的
IT 技術作家,其作品普遍獲得良好評價。(err)
- 2007-11-22 15:39:38下载
- 积分:1
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smithcart
通过matlab和C语言的联合编程实现了微波方面smith圆图的功能(Matlab and C language through the joint programming of the microwave aspects of the function chart smith)
- 2011-04-24 16:26:35下载
- 积分:1
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gingsaoman
意信号卷积的运算,并且绘制图象,包括 MUSIC算法,ESPRIT算法 ROOT-MUSIC算法,ofdm系统仿真 含16qam调制 fft 加窗 加cp等模块。( Convolution operation is intended to signal and image rendering, Including the MUSIC algorithm, ESPRIT algorithm ROOT-MUSIC algorithm, ofdm system simulation including 16qam modulation fft windowing modules plus cp.)
- 2017-05-08 18:17:41下载
- 积分:1
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0
说明: 给定n种物品和一个背包,物品i的重量是Wi,价值是vi,被包容量是C,应该如何选择装入被包的物品,使得装入背包中物品的总价值最大?对于每种物品i,只有两种选择,装入或者不装入.
输入:第一行两个正整数n(物品数)和C(容量)
第二行n个正整数n,表示物品价值
第三行n个正整数n,表示物品重量
输出:第一行表示总价值
第二行n个数(0/1),0表示物品不装入,1表示装入
例如,
输入:
5 10
6 3 5 4 6
2 2 6 5 4
输出
15
1 1 0 0 1
(Species of a given n items and a backpack, the weight of item i is Wi, the value of vi, was packet capacity is C, should be how to choose a package of items to be loaded, the backpack load in the largest total value of goods? For each item i, there are only two options, loaded or not loaded. Input: the first line of the two positive integer n (the number of items) and C (capacity) of the second line of n positive integer n, that the value of the third line of n positive integer n, that the weight of output: the total value of the first line of the second line, said n number of (0/1), 0 that the items do not load, that load 1 for example, enter: 5,106,354,622 6 5 4 output 15 1 1 0 0 1)
- 2009-07-01 23:07:01下载
- 积分:1
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TestLocalHeap
Windows Local heap class
- 2014-11-30 22:26:27下载
- 积分:1
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PrimeNumber
判断一个数是否为素数。可以作为分析研究素数编程的人参考。(To determine whether a number is prime. Analysis of prime numbers can be used as programming easy reference)
- 2009-11-26 11:46:23下载
- 积分:1
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4-6
在屏幕上出现一个圆心沿正弦虚线轨迹移动的实心圆。(In the center of a circle appears on the screen a dotted line along the sinusoidal trajectory moving solid round.)
- 2010-06-28 18:24:37下载
- 积分:1