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Speech-signal-short-time-analysis
The code provides analysis of speech signals for communication
- 2015-03-24 20:14:39下载
- 积分:1
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rs
说明: 给出RS编码和译码的原理
以及解决方案,特别是仿真的一种解决方案,值得参考。(RS gives the principle of encoding and decoding as well as solutions, in particular the simulation of a solution, it is also useful.)
- 2007-11-21 23:31:07下载
- 积分:1
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clipping_papr
找到的一个基本的限幅OFDM峰均比抑制算法matlab仿真程序(Found a basic limiter OFDM PAPR suppression algorithm matlab simulation program)
- 2008-06-18 16:13:18下载
- 积分:1
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Quadrotor_animation_1
Quadrotor Simulation code in Matlab
- 2009-06-23 09:49:19下载
- 积分:1
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timererse
一个计算时间反转镜的例子,已经过测试可以使用(A program of TRM)
- 2012-04-12 00:41:36下载
- 积分:1
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ant colony
蚁群算法的很好范例
matlab代码(ant colony ant algorithm is a good example of Matlab code)
- 2007-04-02 12:44:14下载
- 积分:1
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matlabkejian
matlab基础课件 ,包含matlab基本命令教学(matlab basic courseware contains Matlab basic commands teaching)
- 2012-07-03 20:33:40下载
- 积分:1
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linear_array
利用FFT快速计算,线性排列阵子方向图。( This function computes and returns the gain radiation pattern for a
linear array
It uses the FFT to computes the pattern
*INPUTS**********
Nr ==> number of elements dolr ==> element spacing (d) in lambda units
divided by lambda
theta0 = steering angle in degrees winid ==> use winid negative for no
window, winid positive to enter your window of size(Nr)
win is input window, NOTE that win must be an Nr X 1 row vector nbits ==>
number of bits used in the pahse shifters
negative nbits mean no quantization is used
*OUTPUTS******************
theta ==> real-space angle patternr ==> array radiation pattern in dBs
patterng ==> array directive gain pattern in dBs
***************************************** )
- 2016-03-28 22:30:19下载
- 积分:1
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mnyz
一杯沸水冷却,圆柱体模型,底面半径0.05m,高0.1m,周围温度20度,初始水温100度
方程是四维输运方程(常数a^2=k/(c*p),k是热传导系数0.6006焦/(米*秒*度))
初始条件:t=0时水等于100度
边界条件:1.上下壁都是自由冷却,第三类边界条件,周围温度保持在20度(H=k/h,h取1)
2.杯壁绝热,第二类边界条件
图形显示格式,取过圆柱轴的截面温度变化将其做成动画.
(A cup of boiling water for cooling, the cylinder model, the bottom radius of 0.05m, the high-0.1m, an ambient temperature of 20 degrees, the initial water temperature of 100 degrees is four-dimensional transport equation equation (constant a ^ 2 = k/(c* p), k is the thermal conductivity coefficient of 0.6006 J/(m* s* degrees)) initial conditions: t = 0 when the water equivalent to 100 degrees boundary conditions: 1. up and down the wall are free cooling, the third boundary condition, the ambient temperature maintained at 20 degrees (H = k/h, h check one) 2.杯壁insulation, the second boundary condition graphical display format, check-off section of cylindrical shaft temperature change to make animation.)
- 2007-11-06 20:57:53下载
- 积分:1
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EfficientFrontierGUI
Efficient frontier from Yahoo or database data. (Efficient frontier from Yahoo or database data.)
- 2008-01-15 06:33:04下载
- 积分:1