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lms
均方误差最小LMS算法,s为一个wav格式的音频文件。FIR滤波器长度为5。(LMS)
- 2009-06-11 16:39:41下载
- 积分:1
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Shamir_Sharing
Secret Sharing Scheme
- 2015-02-19 14:56:28下载
- 积分:1
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Pointcharge_matlab
同号点电荷电场的研究的MATLBA程序。有详细说明和解释(Point charge)
- 2009-11-14 12:23:58下载
- 积分:1
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pid
先进PID控制matlab仿真 吊车双摆系统的控制(Advanced PID control simulation matlab)
- 2011-04-28 21:57:15下载
- 积分:1
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dijkstra2
this file present one of the most popular way to calculate dijkstra distance presentation, especialy for 3D triangulation mesh.
- 2011-07-07 02:15:52下载
- 积分:1
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Diffusion-system-of-concentration-
扩散系统之浓度分布的装置。管中储放静止液体B,高度为L=10 ㎝,放置于充满A 气体的
环境中。假设与B 液体接触面之浓度为3
C 0 0.01mol m A = ,且此浓度不随时间改变
而改变,即在操作时间内( h = 10天)维持定值。气体A 在液体B 中之扩散系数为
D m s AB
= 2×10− 9 2 。试决定以下两种情况下,气体A溶于液体B中之流通量(flux)。
(a) A 与B 不发生反应;
(b) A 与B 发生以下之反应
A+ B→C , A A − r = kC
其反应速率常数k = 2×10− 7 s− 1。
(Diffusion system of concentration reference device shown in Figure 3. Tube in the store still liquid B, L = 10 cm height, placed in full A gas environment. Assuming the contact surface of the liquid with the B concentration of 3 C 0 0.01mol m A =, and this concentration does not change with time and change, that is, the operating time (h = 10 days) to maintain constant. Gas A in liquid B, the diffusion coefficient D ms AB = 2 × 10-9 2. Decided the following two test cases, the gas dissolved in liquid B in the A liquid (flux). (A) A and B do not react (b) A and B of the following reaction occurs A+ B → C, AA- r = kC, the reaction rate constant k = 2 × 10-7 s-1.)
- 2011-08-30 22:26:43下载
- 积分:1
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mineGA
genetic algortm for optimation
- 2014-08-28 17:48:04下载
- 积分:1
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simple-BPSK
搭建SISO收发系统,BPSK调制与解调,在白高斯信道下仿真系统BER性能。(Build SISO transceiver system, BPSK modulation and demodulation, the white Gaussian channel simulation system BER performance.)
- 2013-11-10 22:52:59下载
- 积分:1
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mimo
carrier frequency estimation in MIMO OFDM system
- 2009-10-30 19:08:30下载
- 积分:1
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bode
useful to derive the bode plot simple structural formulae
- 2012-04-13 20:03:21下载
- 积分:1