CbCrEllipse

用matlab实现预测的神经网络代码，很实用(Using matlab implementation of the neural network prediction code, a very practical)

说明：  在matlab环境下用智能算法--人工鱼群算法求函数极值的matlab程序(In the matlab environment with intelligent algorithm- artificial fish-swarm algorithm for the extremal function matlab program)

说明：  《MATLAB小波分析》一书源代码，对初学者非常有用(&quot MATLAB wavelet analysis,&quot a book source code, very useful for beginners)

该算法的功能是利用避圈法来求有权图的最小生成树 在函数的编写过程中用到了自己编写的 wode_setdiff(A,b) 函数，具体详参该函数 该算法的实用性相当强，可以实用于任何的赋权有向图最小生成树的求解！！！经过多次不同的运行， 程序的结果都正确无误！(the function is...)

15名基督教徒和15名异教徒同乘一船航行，途中风浪大作，危机万分，领航者告诉大家，只要将全船的一半人投入海中，其余人就能幸免。大家都同意这个办法，并协定者30人围成一圈；由第一个人起报数，每数至第9人便把他投入海中，下一个接着从1开始报数，第9人又被投入海中，依次循环，直至剩下15人为止。问题是如何排法使投入海中的人全为异教徒？(15 Christians and pagans 15 vessels with one by the way, big waves, extreme crisis, leader told everyone that as long as will be half the person boat into the sea, and the remaining person will be able to escape. We all agree that this approach, and agreements were 30 form a circle from the first reported from a few individuals, the number to 9 for each person put him into the sea, then from the next one to start off, 9 people have been invested in the sea, followed by cycle, until the remaining 15 people so far. The question is how to row Act so that the person into the sea all infidels?)

说明：  上采样和内插，使得系统中同时出现的窄带信号和宽带信号能够采用适合本信号的采样率(On sampling and interpolation, making the system at the same time, the narrowband signals and broadband signals can be used for the signal sampling rate)

经典AR模型系数求解，burg法.根据原理手编，希望对大家有帮助。(the method of burg to get the coefficients of AR model)

按照一定的规则，对一定的样品进行分类的程序(According to certain rules, certain procedures for the classification of samples)

利用Ansys进行板建模、划分网格，并初步计算，将Ansys的板的M、K导入到Matlab中，进行振动控制分析，并根据阻尼比自动生成阻尼阵C，绘制频率响应曲线，找到最大值，进行比例控制，并给出控制效果(The board using Ansys modeling, meshing, and preliminary calculations, the Ansys board of M, K imported into Matlab, vibration control analysis, damping automatically according to the damping matrix C, draw the frequency response curve, find the maximum value, the proportional control, and gives control effect)

利用函数MadHG生成规则LDPC码的校验矩阵H，其行重为6,列重为3,行数为列数一半(行数越大越好)，H中任意两列没有围长为4的圈，并得到H对应的生成矩阵G，可以保证mod(G*H ,2)=0。使用方法为:[H,G] = MadHG(m,n,x),x= 1(得到的G左半部分为单位阵) or 2(G右半部分为单位阵),(use function MadHG Generation rules LDPC check matrix H, re-6, series of three, out for a few half of the number (A bigger the better), H 2 arbitrary no girth of the four circles, H counterparts and with the formation of matrix G, we can be assured of mod (G* H, 2) = 0. To be used : [H, G] = MadHG (m, n, x), x = 1 (the G part of the Left Front units) or 2 (G right half of the units RUF),)