MCM

CCISP考试指南与导读 CISSP STUDY NOTES FROM CISSP PREP GUIDE 1 DOMAIN 1 – SECURITY MANAGEMENT PRACTICES 2 DOMAIN 2 – ACCESS CONTROL SYSTEMS 7 DOMAIN 3 – TELECOM AND NETWORK SECURITY 13 DOMAIN 4 – CRYPTOGRAPHY 34 DOMAIN 5 – SECURITY ARCHITECTURE AND MODELS 46 DOMAIN 6 – OPERATIONS SECURITY 56 DOMAIN 7 – APPLICATIONS AND SYSTEM DEVELOPMENT 63 DOMAIN 8 – BUSINESS CONTINUITY AND DISASTER RECOVERY PLANNING 70 DOMAIN 9 – LAW, INVESTIGATION AND ETHICS 78 DOMAIN 10 – PHYSICAL SECURITY 87(CCISP test guidelines and guidance CISSP STUDY NOTES FROM CISSP PREP GUIDE 1DOMAIN 1- SECURITY MANAGEMENT PRACTICES 2DOMAIN 2- ACCESS CONTROL SYSTEMS 7DOMAIN 3- TELECOM AND NETWORK SECURITY 13DOMAIN 4- CRYPTOGRAPHY 34DOMAIN 5- SECURITY ARCHITECTURE AND MODELS 46DOMAIN 6- OPERATIONS SECURITY 56DOMAIN 7-- APPLICATIONS AND SYSTEM DEVELOPMENT 63DOMAIN 8- BUSINESS CONTINUITY AND DISASTER RECOVERY PLANNING 70DOMAIN 9- LAW, INVESTIGATION AND ETHICS 78DOMAIN 10- PHYSICAL SECURITY 87)

无线通信物理层信道建模，链路衰落，LDPC编码，OFDM，及智能天线等等关于物理层的码源(Wireless communication channel modeling the physical layer, link the decline, LDPC codes, OFDM, and smart antennas, and so the source code on the physical layer)

建立了强湍流模式下无线光通信模型，并在模型的基础上讨论了SISO与SIMO中的误码率。(Strong turbulence mode optical wireless communication model, and discussed in the model based on the error rate in SISO and SIMO.)

用matlab来评价金属元素污染程度，以判断污染的程度，其中污染的程度又分为不同等级。(use matlab to descripe metal)

HYBRID pso OPTIMIZATION

根据信息熵建立分配模型，接着用熵值法进行合理分配的程序(Established based on information entropy distribution model, followed by entropy reasonable allocation procedures)

基于Matlab的一个最简单的人脸检测程序 ,本程序是基于肤色的人脸侦测程序，较为简单(Based on Matlab a simple face detection program, the program is based on the color of the face detection process, a relatively simple)

计算矢量所在扇区的N模型，判断当前的扇区(calculating vector lies Sector N model, the current portion of the judgment)

三维图形的拟合程序，两列输入数据，一列输出数据(The fitting procedure of 3D graphics )

A 4 bit twisted ring counter is a sequential circuit which produces the following sequence of output values: 0000, 1000, 1100, 1110, 1111, 0111, 0011, 0001 and then repeats. Design a circuit for a 4 bit twisted ring counter that uses four D flip flops. Draw a state transition diagram, a state table and a schematic for your circuit. Design an alternate implementation using just three flip flops and draw a state transition diagram, state table and a schematic for your circuit. If your designs are extended to implement an n bit twisted ring counter, how many flip flops are required using each of the two approaches. In what situations would you prefer the first method? In what situations would you prefer the second?