PAPR

SHAPE FROM SHADING FOR EIKONAL PROBLEMS

直接序列扩频利用与信息无关的伪随机码，以调制方法将已调制信号的频谱宽度扩展得比原调制信号的带宽宽得多的过程。(Direct sequence spread spectrum has nothing to do with the information of pseudo-random code modulated signal spectrum width modulation method will be extended than the original modulation signal bandwidth is much wider process. )

Beamspace ESPRIT方法在MIMO雷达角度估计中是实现，有仿真后的结果对比(Beamspace ESPRIT angle estimation method in MIMO radar is realized, after the simulation results comparison)

基于matlab 2010rb搭建的buck-boost chopper直流变换器升降压斩波电路仿真模型，调试通过，适合本科生学习电力电子技术仿真。(2010 rb based on matlab to build the buck- boost chopper dc converter buck chopper circuit simulation model, debugging through, suitable for undergraduate study power electronic technology simulation.)

openMP merge sort code.

cdi_readfield.m cdi_readfield.mcdi_readall.mexw32 cdi_readfull.mexw32 cdi_readfield.m matlab的一些程序，希望大家在学习中可以用到(matlab studying)

we create uniform network using matlab

matlab调用CTP接口的例子，实用性强(the matlab call CTP interfaces examples of practical)

产生右图所示图像f1(m,n)，其中图像大小为256×256，中间亮条为128 ×32，暗处=0，亮处=100。对其进行FFT： ① 同屏显示原图f1(m,n)和FFT(f1)的幅度谱图； ② 若令f2(m,n)=（-1）m+n f1(m,n)，重复以上过程，比较二者幅度 谱的异同，简述理由； ③ 若将f2(m,n)顺时针旋转90 度得到f3(m,n)，试显示FFT(f3)的幅 度谱，并与FFT(f2)的幅度谱进行比较； ④ 若将f1(m,n) 顺时针旋转90 度得到f4(m,n)，令f5(m,n)=f1(m,n)+f4(m,n)，试显 示FFT(f5)的幅度谱，并指出其与FFT(f1)和FFT(f4)的关系； ⑤ 若令f6(m,n)=f2(m,n)+f3(m,n)，试显示FFT(f6)的幅度谱，并指出其与FFT(f2)和 FFT(f3)的关系，比较FFT(f6)和FFT(f5)的幅度谱。(Generating an image f1 (m, n) shown in the figure, wherein the image size is 256 256, the intermediate light bar 128 32 0 = dark, bright Department 100. Its FFT: ① screen display picture f1 (m, n) and the FFT (f1) of the amplitude spectrum ② If so f2 (m, n) = (-1) m+n f1 (m, n), repeat The above process, comparing the amplitude spectrum of the similarities and differences between the two, brief reasons ③ If f2 (m, n) 90 degrees clockwise to get f3 (m, n), try to display FFT (f3) the amplitude spectrum and with the FFT (f2) comparing the amplitude spectrum ④ If f1 (m, n) obtained by 90 degrees clockwise f4 (m, n), so f5 (m, n) = f1 (m, n)+f4 (m, n ), try to display FFT (f5) amplitude spectrum, and pointed out its relationship with the FFT (f1) and FFT (f4) of ⑤ If so f6 (m, n) = f2 (m, n)+f3 (m, n) and try to display the FFT (f6) amplitude spectrum, and pointed out its relationship with the FFT (f2) and FFT (f3), comparing FFT (f6) and FFT (f5) amplitude spectrum.)

说明：  按照书本上教材编写的自适应中值滤波函数，很有参考价值(Materials prepared in accordance with the books adaptive median filtering function, a good reference)